Q. For a chemical reaction $2X + Y \rightarrow Z,$ the rate of appearance of $Z$ is $0.05\ mol\ L^{- 1}.$ The rate of disappearance of $X$ will be
A) $0.05\ mol\ L^{- 1}\ h^{- 1}$
B) $0.05\ mol\ L^{- 1}\ \min^{- 1}$
C) $0.1\ mol\ L^{- 1}\ \min^{- 1}$
D) $0.25\ mol\ L^{- 1}\ \min^{- 1}$
Explanation
(c)
For the reaction,
$2X + Y \rightarrow Z$
$Rate = - \frac{1}{2}\frac{d\lbrack X\rbrack}{dt} = \frac{d\lbrack Z\rbrack}{dt}$
$= 0.05\ mol\ L^{- 1}\ \min^{- 1}$
$- \frac{1}{2}\frac{d\lbrack X\rbrack}{dt} = 0.05$
$- \frac{d\lbrack X\rbrack}{dt} = 2 \times 0.05$
$= 0.1\ mol\ L^{- 1}\ \min^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.