Q. The rate of a gaseous reaction is equal to $k\lbrack A\rbrack\lbrack B\rbrack.$ The volume of the reaction vessel containing these gases is reduced by one-fourth of the initial volume. The rate of the reaction would be
A) $\frac{1}{16}$
B) $\frac{16}{1}$
C) $\frac{1}{8}$
D) $\frac{8}{1}$
Explanation
(b)
Rate $(r) = k\lbrack A\rbrack\lbrack B\rbrack = kab$
When volume is reduced by one fourth then concentration becomes 4 times
Hence, $r^{'} = k(4a)(4b)$
$= 16kab$
$\therefore r^{'} = 16r$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.