Q. The rate law for the reaction $RCl + NaOH \rightarrow ROH + NaCl$ is given by $Rate = k\lbrack RCl\rbrack.$ The rate of this reaction
A) Is doubled by doubling the concentration of $NaOH$
B) Is halved by reducing the concentration of $RCl$ by one half
C) Is increased by increasing the temperature of the reaction
D) In unaffected by change in temperature
Explanation
(b)
$RCl + NaOH \rightarrow ROH + NaCl$
$Rate = k\lbrack RCl\rbrack$
For this reaction rate of reaction is depends upon the concentration of $RCl$
It means, the rate of reaction is halved by reducing the concentration of $RCl$ by one half
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.