For a first order reaction, the initial concentration of a reactant is 0.05 M. After 45 min it is decreased by 0.015 M. calculation half reaction time $\left( t_{1/2} \right)$

Question

Dr. Abubacker · Accepted Answer

(a)
For first order reaction
$k = \frac{2.303}{t}\log\frac{\lbrack A_{0}brack}{\lbrack Abrack}$
$k = \frac{2.303}{45}\log\frac{0.05}{0.035}$
$k = \frac{2.303}{45}\log{1.42}$
$k = \frac{2.303 	imes 0.1523}{45} = 0.0078$
$t_{1/2} = \frac{0.693}{0.0078} = 88\ min$

Q. For a first order reaction, the initial concentration of a reactant is 0.05 M. After 45 min it is decreased by 0.015 M. calculation half reaction time $\left( t_{1/2} \right)$

Explanation

Reviewed by Dr. Abubacker

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