Q. For the reaction $H_{2}(g) + {Br}_{2}(g) \rightarrow 2HBr(g)$ The experimental data suggest $rate = k\left\lbrack H_{2} \right\rbrack\left\lbrack {Br}_{2} \right\rbrack^{1/2}$ the molecularity and order of the reaction are respectively
A) $1,\frac{1}{2}$
B) $1,\ 1$
C) $\frac{3}{2},\frac{3}{2}$
D) $2,\frac{3}{2}$
Explanation
(d)
For the reaction $H_{2}(g) + {Br}_{2}(g) \rightarrow 2HBr(g)$
Rate of reaction $= k\left\lbrack H_{2} \right\rbrack\left\lbrack {Br}_{2} \right\rbrack^{1/2}$
Molecularity of reaction $= 1 + 1 = 2$
Order of reaction $= 1 + \frac{1}{2} = \frac{3}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.