Q. For the reaction $N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}$ The rate of change of concentration for hydrogen is $0.3 \times 10^{- 4}Ms^{- 1}$ The rates of change of concentration of ammonia is
A) $- 0.2 \times 10^{- 4}$
B) $0.2 \times 10^{- 4}$
C) $0.1 \times 10^{- 4}$
D) $0.3 \times 10^{- 4}$
Explanation
(b)
$N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}$
$\frac{d\left\lbrack H_{2} \right\rbrack}{dt} = - 0.3 \times 10^{- 4}ms^{- 1}$
$rate = - \frac{1}{3}\frac{d\left\lbrack H_{2} \right\rbrack}{dt} = + \frac{1}{2}\frac{d\left\lbrack NH_{3} \right\rbrack}{dt}$
$= \frac{d\left\lbrack NH_{3} \right\rbrack}{dt} = - \frac{2}{3}\frac{d\left\lbrack H_{2} \right\rbrack}{dt}$
$= - \frac{2}{3} \times ( - 0.3 \times 10^{- 4})$
$= 0.2 \times 10^{- 4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.