Q. For the decomposition of $N_{2}O_{5}$ at a particular temperature, according to the equations $2N_{2}O_{5} \rightarrow 4{NO}_{2} + O_{2}$ $N_{2}O_{5} \rightarrow 2{NO}_{2} + \frac{1}{2}O_{2}$ The activation energies are $E_{1}\$and $E_{2}$ respectively then
A) $E_{1} > E_{2}$
B) $E_{1} < E_{2}$
C) $E_{1} = 2E_{2}$
D) $E_{1} = E_{2}$
Explanation
(d)
Activation energy of a reaction is constant at constant temperature hence, $E_{1} = E_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.