Q. For the reaction system, $2NO(g) + O_{2}(g) \rightarrow 2NO_{2}(g)$ Volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order with respect to $O_{2}$ and second order with respect to NO; the rate of reaction will
A) Diminish to one –fourth of its initial value
B) Diminish to one –eighth of its initial value
C) Increase to eight time of its initial value
D) Increase to four time of its initial value
Explanation
(c)
$\left( \frac{dx}{dt} \right) = k\lbrack NO\rbrack^{2}\lbrack o_{2}$]
$= k\left( \frac{n_{NO}}{V} \right)^{2}\left( \frac{n_{O_{2}}}{V} \right)$
$\left( \frac{dx}{dt} \right) = \frac{k}{V^{3}}\left( n_{No} \right)^{2}\left( n_{O_{2}} \right)$
$\left( \frac{dx}{dt} \right) = \frac{k\left( n_{No} \right)^{2}\left( n_{O_{2}} \right)}{\left( \frac{V}{2} \right)^{3}}$
$= 8\left( \frac{dx}{dt} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.