Q. The velocity constant of a reaction at 290 K was found to be $3.2 \times 10^{- 3}$at 300 K, it will be
A) $6.4 \times 10^{- 3}$
B) $1.28 \times 10^{- 2}$
C) $9.6 \times 10^{- 3}$
D) $3.2 \times 10^{- 4}$
Explanation
(a)
The ratio of rate constant when temperature is raised$\ 10℃$, is called temperature coefficient. For most of the reaction, it has a value of 2.
Hence, for the given reaction,
Rate constant at 290 K=$3.2 \times 10^{- 3}$
$\therefore$ Rate constant at 300 K=$2 \times 3.2 \times 10^{- 3}$
$= 6.4 \times 10^{- 3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.