(b) $k = \frac{2.303}{t}\log_{10}\frac{a}{a - x}$ $= \frac{2.303}{10}\log_{10}\frac{100}{80}$ $= \frac{2.303}{10}\ \left\lbrack \log{10 - 3}\log 2 \right\rbrack$ $\ = \frac{2.303}{10}\ \lbrack 1 - 3 \times 0.3010\rbrack$ $k = 0.0223$
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Ph.D. in Physics with 19+ years of teaching experience.