Q. Consider an endothermic reaction $X \rightarrow Y$ with the activation energies $E_{b}\ and\ E_{f}$ for the backward and forward reactions respectively. In general
A) There is no definite relation between $E_{b}\ and\ E_{f}$
B) $E_{b} = E_{f}$
C) $E_{b} > E_{f}$
D) $E_{b} < E_{f}$
Explanation
(d)
$X \rightarrow Y$ is an endothermic reaction $\mathrm{\Delta}H$=+ ve
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$E_{b} =$energy of activation of backward reaction
$E_{f} =$energy of activation of forward reaction
$\mathrm{\Delta}H =$ heat of reaction
Thus, $E_{f} = E_{b} + \mathrm{\Delta}H$
Thus, $E_{f} > E_{b}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.