Q.
For a first order reaction the graph $\log{\ \lbrack A\rbrack}vs\ t$ is given below
$x$ is equal to
A) $\frac{0.693}{k}$
B) $\frac{k}{2.303}$
C) $- \frac{k}{2.303}$
D) $\log{\ \lbrack A\rbrack}_{0}$
Explanation
(c)
For first order reaction
$\log\lbrack A\rbrack = - \frac{kt}{2.303} + \log\lbrack A\rbrack_{0}$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.