Q. For the reaction $A \rightarrow B,$ the rate expression is $r = k\lbrack A\rbrack^{n}.$ When the concentration of $A$ is doubled, the rate of reaction is quadrupled. The value of $n$ is

A) 1
B) Zero
C) 3
D) 2
Explanation

(d)
$r = k\lbrack A\rbrack^{n}\ \ \ \ \ \ \ \ \ \$ …(i)
When concentration is doubled then
$4r = k(2A)^{n}\ \ \ \ \ \ \$…(ii)
Divide Eq. (ii) by (i)
$4 = 2^{n}$
$n = 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.