In a reaction$\ A + B \rightarrow C$, the rate expression is$\ R = k\lbrack A\rbrack\lbrack B\rbrack^{2}$. If the concentration of both the reaction is doubled at constant volume then the rate of the reaction will be

Question

Dr. Abubacker · Accepted Answer

(a)
Given ,$\ R = k\lbrack A\rbrack\lbrack B\rbrack^{2}$
Where [A]=[2A]and B=[2B]
$R' = k\lbrack 2A\rbrack\lbrack 2B\rbrack^{2}$
$= k\lbrack 2A\rbrack 4\lbrack B\rbrack^{2}$
$= 8k\lbrack A\rbrack\lbrack B\rbrack^{2}$
R’=8R
Thus, the rate will become eight times

Q. In a reaction$\ A + B \rightarrow C$, the rate expression is$\ R = k\lbrack A\rbrack\lbrack B\rbrack^{2}$. If the concentration of both the reaction is doubled at constant volume then the rate of the reaction will be

Explanation

Reviewed by Dr. Abubacker

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