Q. A reaction $A \rightarrow B$ follows a second order kinetics. Doubling the concentration of A will increase the rate of formation of B by a factor of
A) ¼
B) 4
C) ½
D) 2
Explanation
(b)
For second order reaction
$r = k\lbrack A\rbrack^{2\ \ \ \ \ \ \ \ }\ \ \ \ \ \ \ \ \ldots(1)$
When concentration of A(reactant)is doubled
$r' = k\lbrack 2A\rbrack^{2\ \ \ \ \ \ \ \ }$
$r^{'} = 4k\lbrack A\rbrack^{2\ \ \ \ \ \ \ \ }\ \ \ldots(2)$
Comparing Eqs.(1)and(2)
r’ =4r
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.