Q. A reaction involving A, B and C as reactants is found to obey the rate law, rate=$k\lbrack A\rbrack^{x}\lbrack B\rbrack^{y}\lbrack C\rbrack^{z}$. When the concentration of A, B and C are doubled separately, the rate is also found to increase two, zero and four times respectively. The overall order of the reaction is
A) 1
B) 2
C) 3
D) 4
Explanation
(c)
$\because$ On doubling the concentration of A, the rate of reaction becomes two times.
$\therefore$ The order of reaction w.r.t. A is 1
$\because$ On doubling the concentration of B, the rate of reaction does not change.
$\therefore$ the order of reaction respect to B is 0
$\because$ on doubling the concentration of C, the rate of reaction becomes four times
$\therefore$ the order of reaction w.r.t. C is 2
$\therefore$ the overall order of reaction=1+0+2=3
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.