Q. The rate of the reaction ${CCl}_{3}CHO + NO \rightarrow {CHCl}_{3} + NO + CO$ is equal to rate $k\left\lbrack {CCl}_{3}CHO \right\rbrack\lbrack NO\rbrack.$ If concentration is expressed in mol/L. The unit of $k$ is
A) $L\ {mol}^{- 1}\ s^{- 1}$
B) $mol\ L^{- 1}\ s^{- 1}$
C) $L^{2}\ {mol}^{- 2}\ s^{- 1}$
D) $s^{- 1}$
Explanation
(a)
For the reaction :
${CCl}_{3}CHO + NO \rightarrow CHCl_{3} + NO + CO$
$Rate = \frac{dx}{dt} = k\left\lbrack {CCl}_{3}CHO \right\rbrack\lbrack NO\rbrack$
$k = \frac{dx}{dt \times \left\lbrack {CCl}_{3}CHO \right\rbrack\lbrack NO\rbrack}$
$= \frac{mol/L}{s \times mol/L \times mol/L}$
$k = L\ {mol}^{- 1}\ s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.