For a reaction between gaseous compounds, $2A + B \rightarrow C + D$ The reaction rate=k[A][B]. If the volume of the container is made $\frac{1}{4}$ of the initial, then what will be the rate of reaction as compared to the initial rate?

Question

Dr. Abubacker · Accepted Answer

(a)
When volume is reduced to one fourth, concentration become four times. Hence, the rate of reaction becomes 16 times as compared to the initial rate.

Q. For a reaction between gaseous compounds, $2A + B \rightarrow C + D$ The reaction rate=k[A][B]. If the volume of the container is made $\frac{1}{4}$ of the initial, then what will be the rate of reaction as compared to the initial rate?

Explanation

Reviewed by Dr. Abubacker

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