(a)
$2{FeCl}_{3} + {SnCl}_{2} \rightarrow 2{FeCl}_{2} + {SnCl}_{4}$
It is a third order reaction. As the concentration of both ${FeCl}_{3}\ and\ {SnCl}_{2}$ affect the rate of reaction
$\therefore Rate = k\left\lbrack {FeCl}_{3} \right\rbrack^{2}\left\lbrack {SnCl}_{2} \right\rbrack$
Hence, order of reaction $= 2 + 1 = 3$