(c)
[image:4_image24.emf]
Where,
$E_{a} =$activation energy of forward reaction
$E_{a}^{''}$=activation energy of backward reaction
The above energy profile diagram shows that
$E_{a} > E_{a}^{''}$
The potential energy of the product is greater than that of the reactant, so the reaction is endothermic.
$E_{a} = E_{a}^{''} + \mathrm{\Delta}E$
$E_{t} = E_{a}$ or $E_{t} > E_{a}^{''}$