Q. The rate constant for the reaction $2N_{2}O_{5} \rightarrow 4{NO}_{2} + O_{2}\$is$\ 3.0 \times 10^{- 5}\ s^{- 1}.$ If the rate is $2.40 \times 10^{- 5}\ mol\ L^{- 1}\ s^{- 1},$ then the concentration of ${\ N}_{2}O_{5}$ is $mol\ L^{- 1}$ is
A) 0.4
B) 0.8
C) 1.2
D) 3.2
Explanation
(b)
Rate $= k\left\lbrack N_{2}O_{5} \right\rbrack$
$2.4 \times 10^{- 5} = 3.0 \times 10^{- 5}\left\lbrack N_{2}O_{5} \right\rbrack$
$\left\lbrack N_{2}O_{5} \right\rbrack = \frac{2.4 \times 10^{- 5}}{3.0\ \times 10^{- 5}} = 0.8\ mol\ L^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.