For a reaction,$x(g) \rightarrow y(g) + z(g)$ the half-life period is 10 min. in what period of time would the concentration of X be reduce to 10% of original concentration?

Question

Dr. Abubacker · Accepted Answer

(b)
$X(g) ightarrow Y(g) + Z(g)$
The reaction is a first order reaction.
Hence ,
$k = \frac{0.693}{t_{1/2}} = \frac{2.303}{t}\log\frac{a}{(a - x)}$
$02234\ \frac{0.693}{10} = \frac{2.303}{t}\log\frac{a}{a/10}$
Or $t = \frac{2.303 	imes 10}{0.693} 	imes \log 10$
=33min

Q. For a reaction,$x(g) \rightarrow y(g) + z(g)$ the half-life period is 10 min. in what period of time would the concentration of X be reduce to 10% of original concentration?

Explanation

Reviewed by Dr. Abubacker

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