Q. $2N_{2}O_{5}\text{⇌}4NO_{2} + O_{2}$ For the above reaction which of the following is not correct above rates of reaction?
A) $\frac{- d\lbrack N_{2}O_{5}\rbrack}{dt} = 2\frac{d\lbrack O_{2}\rbrack}{dt}$
B) $\frac{- 2d\lbrack N_{2}O_{5}\rbrack}{dt} = \frac{d\lbrack NO_{2}\rbrack}{dt}$
C) $\frac{d\lbrack NO_{5}\rbrack}{dt} = 4\frac{d\lbrack O_{2}\rbrack}{dt}$
D) $\frac{- 2d\lbrack N_{2}O_{5}\rbrack}{dt} = 4\frac{d\lbrack NO_{2}\rbrack}{dt} = \frac{d\lbrack O_{2}\rbrack}{dt}$
Explanation
(d)
$2N_{2}O_{5} \rightleftharpoons 4NO_{2} + O_{2}$
$Rate = \pm \frac{1}{\begin{array}{r}
stoichiometrics\ \ \\
coefficient
\end{array}}\frac{d\lbrack product\ or\ reactant}{dt}$
$\therefore Rate = \ \frac{- 1}{2}\frac{d\lbrack N_{2}O_{5}\rbrack}{dt} = + \frac{1}{4}\frac{d\lbrack NO_{2}\rbrack}{dt} = \frac{d\lbrack O_{2}\rbrack}{dt}$
$Or\ \ \ \ \ - \frac{d\lbrack N_{2}O_{5}\rbrack}{dt} = 2\frac{d\lbrack O_{2}\rbrack}{dt}$
$Or\ \ \ \ \frac{- 2d\lbrack N_{2}O_{5}\rbrack}{dt} = 4\frac{d\lbrack NO_{2}\rbrack}{dt}$
$Or\ \ \ \frac{d\lbrack NO_{2}\rbrack}{dt} = \frac{4d\lbrack O_{2}\rbrack}{dt}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.