(a) $2A + B \rightarrow A_{2}B$ $r_{1} = k\lbrack A\rbrack^{2}\lbrack B\rbrack$ $r_{2} = k\lbrack 2A\rbrack^{2}\lbrack B/2\rbrack$ Or $\ r_{2} = 2k\lbrack A\rbrack^{2}\lbrack B\rbrack$ $\therefore r_{2} = 2r_{1}$
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Ph.D. in Physics with 19+ years of teaching experience.