Q. The rate constant of a first order reaction at $27℃$ is $10^{- 3}\ min^{- 1}$. The temperature coefficient of this reaction is 2. What is the rate constant (in $min^{- 1}$) at $17℃$ for this reaction?
A) $10^{- 3}$
B) $5 \times 10^{- 4}$
C) $2 \times 10^{- 3}$
D) $10^{- 2}$
Explanation
(b)
Temperature coefficient,
$= \frac{k_{t} + 10}{k_{t}}$
$2 = \frac{10^{- 3}}{k_{t}}$
$k_{t} = \frac{10^{- 3}}{2} = \frac{10 \times 10^{- 4}}{2} = 5 \times 10^{- 4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.