A) Saponification of $CH_{3}COOC_{2}H_{5}$ -second order reaction
B) Hydrolysis of $CH_{3}COOCH_{3}$ -pseudo unimolecular
C) Decomposition of $H_{2}O_{2}$ -first order reaction
D) Combination of $H_{2}\ and\ Br_{2}$to give HBr -first order reaction
Explanation
(d)
Combination of $H_{2}$and $B_{r2}$ to give HBr is zero order reaction as the rate of reaction is not affected by the concentration of reactants.
$H_{2} + B_{r2}\overset{hv}{\rightarrow}$ 2HBr
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.