(d)
$t_{1/2} = \frac{1}{(a)^{n - 1}}$
Where, n=order of reaction
a= initial concentration
For first order reaction,
n=1
$t_{1/2} = \frac{1}{a^{n - 1}}$
$a = \frac{1}{a^{0}} = 0$
Thus for a first order reaction,$t_{1/2}$ is independent of initial concentration.