Q. If $(x/m)$ is the mass of adsorbate adsorbed per unit mass of adsorbent. pis the pressure of the adsorbate gas and $a$ and $b$ are constants, which of the following represents “Langmuir adsorption isotherm”?
A) $\log\left( \frac{x}{m} \right) = \log\left( \frac{a}{b} \right) + \frac{1}{a}\log p$
B) $\frac{x}{m} = \frac{b}{a} + \frac{1}{ap}$
C) $\frac{x}{m} = \frac{1 + bp}{ap}$
D) $\frac{1}{(x/m)} = \frac{b}{a} + \frac{1}{ap}$
Explanation
(d)
If $x/m$ is the mass of adsorbate per unit mass of adsorbent,$\ p$ is the pressure of adsorbate gas and $a\ and\ b$ are constants, then Langmuir adsorption isotherm is given as
$\frac{x}{m} = \frac{ap}{1 + bp}$
or $\frac{1}{x/m} = \frac{1 + bp}{ap}$
$\frac{1}{x/m} = \frac{1}{ap} + \frac{b}{a}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.