Q. In Zeigler-Natta polymerisation of ethylene, the active species is :
A) $AlCl_{3}$
B) $Et_{3}Al$
C) $CH_{2}CH_{2}$
D) $Ti^{III}$
Explanation
(d)
Zeigler-Natta catalyst is formed by the action of $\left( C_{2}H_{5} \right)_{3}Al$ and ${TiCl}_{4}$. The active species is $Ti^{III}$ as $\left( C_{2}H_{5} \right)_{3}$Al can reduce $TiCl_{4}$ to $TiCl_{3}$. $Ti^{III}$ has one active site vacant and thus accommodates one alkyl group.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.