(d)
$PbO$ and $PbSO_{4}$ get reduced by $PbS$ itself which is already present in mixture, because the reduction takes place by mixture itself, hence is known as self reduction
$2PbO + PbS\overset{\mathrm{\Delta}}{\rightarrow}3Pb + SO_{2} \uparrow$
$PbSO_{4} + PbS\overset{\mathrm{\Delta}}{\rightarrow}2Pb + 2SO_{2} \uparrow$