Q. A green yellow gas reacts with an alkali metal hydroxide to form a halate which can used in fireworks and safety matches. The gas and halate respectively are
A) $Br_{2},\ KBrO_{3}$
B) $Cl_{2},\ KClO_{3}$
C) $I_{2},\ NaIO_{3}$
D) $Cl_{2},NaClO_{3}$
Explanation
(b)
A halate will be formed from halogen and the greenish yellow gas is $Cl_{2}$. The halate which is used in fireworks and safety matches is $KClO_{3}$
$3Cl_{2} + 6KOH \rightarrow KClO_{3} + 5HCl + 3H_{2}O$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.