(c)
The end product of the hydrolysis of XeF_{6} is XeO_{3}
XeF_{6}$\frac{H2O}{- 2HF}$ XeOF_{4}$\frac{H2O}{- 2HF}$ XeO_{2}F_{2}$\frac{H2O}{- 2HF}$ XeO_{3}
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.