Q. At T (K), 100 L of dry oxygen is present in a sealed container. It is subjeceted to silent electric discharge, till the volumes of oxygen and ozone becomes equal .what is the volume of ozone formed at T (K)?
A) 50
B) 60
C) 30
D) 40
Explanation
(d)
3O_{2}⟶2O_{3}
3vol O_{2}=2vol O_{3}
$x$ vol O_{2}=$\frac{2}{3}x$ vol O_{3}
$x$+$\frac{2}{3}$ $x$ =100L
$\frac{5}{3}x\$=100 or $x$=60L O_{2}
Volume of O_{3}=$\frac{2}{3}$⨯60=40L
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.