Q. Excess of PCl_{5} reacts with conc. H_{2}SO_{4} giving
A) Chlorosulphonic acid
B) Thionyl chloride
C) Sulphuryl chloride
D) Sulphurous acid
Explanation
(c)
PCl_{5} reacts with conc. H_{2}SO_{4} to give sulphuryl chloride by replacing its hydroxyl group with chlorine atoms.
SO_{2}(OH)_{2} + 2PCl_{5}⟶SO_{2}Cl_{2}+2POCl_{3}+2HCl
_{or}
H_{2}SO_{4 sulphuryl chloride}
_{sulphuric acid}
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.