Q. SO_{2} + H_{2}S⟶ product. The final product is
A) H_{2}O+S
B) H_{2}SO_{4}
C) H_{2}SO_{3}
D) H_{2}S_{2}O_{3}
Explanation
(a)
In the reaction SO_{2} and H_{2}S, SO_{2} acts as oxidizing agent and H_{2}S acts as reducing agent.
SO_{2}+2H_{2}S⟶2H_{2}O+3s↓
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.