Q. What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?
A) $CrO_{4}^{2 -}$ is reduced to +3 state of Cr
B) $CrO_{4}^{2 -}$ is oxidized to + 7 state of Cr
C) ${{Cr}_{2}O}_{7}^{2 -}$ and $H_{2}O$ are formed
D) $Cr^{3 -}and\ {{Cr}_{2}O}_{7}^{2 -}\ \$ are formed
Explanation
(c)
$2Cr_{4}^{2 -} + 2H^{+} \rightarrow Cr_{2}O_{7}^{2 -} + H_{2}O$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.