Q. $Cl_{2}$ reacts with $CS_{2}$ in presence of $I_{2}$ catalyst to form
A) $CHCl_{3}$
B) $C_{2}H_{5}Cl$
C) $CCl_{4}$
D) $C_{2}H_{6}$
Explanation
(c)
$CS_{2} + 3Cl_{2}\overset{{\ \ I}_{2}\ \ }{\rightarrow}\ CCl_{4} + S_{2}Cl_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.