(d)
NaNO_{2} + NH_{4}OH⟶ NH_{4}NO_{2}+NaOH
NH_{4}NO_{2}⟶N_{2}+2H_{2}O
$\because\$NH_{4}NO_{2} is unstable, so it is prepared by reaction of NaNO_{2} and NH_{4}OH.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.