Q. In compounds of type $ECl_{3}$, where $E = B,\ P,$ As or Bi the angles $Cl - E - Cl$ for different $E$ are in the order
A) $B > P > As > Bi$
B) $B > P = As = Bi$
C) $B < P = As = Bi$
D) $B < P < As < Bi$
Explanation
(a)
B > P > As > Bi
As we go down the group, bond angle decreases, since the repulsion between the bonded pairs of electrons decrease
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.