Q. Amongst $H_{2}O,\ H_{2}S,\ H_{2}Se\ and\ H_{2}Te$ one having higher b.pt. is
A) $H_{2}S$ because of hydrogen bonding
B) $H_{2}Se$ because of lower molecular weight
C) $H_{2}Te$ because of higher molecular weight
D) $H_{2}O$ because of hydrogen bonding
Explanation
(d)
$H_{2}O$ containing H-bond due to which it have highest boiling point
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.