Q. The oxidation state of Xe and XeO_{3} and the bond angle in it respectively are
A) +6, 109${^\circ}$
B) +8, 103${^\circ}$
C) +6, 103${^\circ}$
D) +8, 120${^\circ}$
Explanation
(c)
The oxidation state of Xe in XeO_{3} can be calculated as
XeO_{3,} $x$+(-2$\times 3) = 0$
$X$=+6
XeO_{3} has Sp^{3} hybridisation with bond angle =103${^\circ}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.