Q. Which one liberates $Br_{2}$ from $KBr$?
A) $I_{2}$
B) $HI$
C) $Cl_{2}$
D) $SO_{2}$
Explanation
(c)
$Cl_{2} + 2KBr \rightarrow Br_{2} + 2KCl$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.