Q. The treatment of Cu with dilute HNO_{3} gives
A) N_{2}O
B) NO
C) NH_{4}^{+}
D) NO_{2}
Explanation
(a)
4Cu+10 HNO_{3}⟶4Cu(NO_{3})_{2}+5H_{2}O+N_{2}O
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.