Q. The magnetic moment of a transition metal ion is 3.87 BM. The number of unpaired electrons present in it is
A) 2
B) 3
C) 4
D) 5
Explanation
(b)
3.87=$\sqrt{n(n + 2)}$, where, $n$ is the number of unpaired electron
$\ \ \ \ \ \ \ \ (3.87\ )^{2}$ =$\ n$($n$ +2)
15=$\ n^{2} + 2n$
$n^{2}$+2$\ n$ -15=0
$\therefore$ $n\ \cong 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.