Q. Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them?
A) $(n - )d^{8},ns^{2}$
B) $(n - 1)d^{5},ns^{1}$
C) $(n - 1)d^{3},ns^{2}$
D) $(n - 1)d^{5},ns^{2}$
Explanation
(d)
Maximum oxidation state exhibited by $d$-block elements (O.S.) =no of $ns$ electrons + no. of ($n - 1$)$d$ electrons.
(a) O.S.=2+2=4 (b) O.S.=5+1=6
(c) O.S.=3+2=5 (d) O.S=5+2=7
($n - 1$) $d^{5}\ ns^{2}$ configuration will achieve the highest oxidation state.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.