Q. Excess of KI reacts with ${CuSO}_{4}$ solution and then ${Na}_{2}S_{2}O_{3}$ solution is added to it. Which of the statements is incorrect for this reaction?
A) ${Cu}_{2}I_{2}$ formed
B) ${Cul}_{2}$ is formed
C) ${Na}_{2}S_{2}O_{3}$ is oxidised
D) Evolved $I_{2}$ is reduced
Explanation
(b)
${CuSO}_{4} + 2KI\ \longrightarrow {Cul}_{2} + K_{2}{SO}_{4}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ unstable$
$2{CuI}_{2} \longrightarrow {Cu}_{2}I_{2} + I_{2}$
$Thus,\ {CuI}_{2}\ \ is\ not\ formed.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.