Q. The spin only magnetic moment of ${Fe}^{2 +}$ ion (in BM) is approximately.
A) 4
B) 7
C) 5
D) 6
Explanation
(b)
_{26}Fe =[Ar]$3d^{5}\ 4s^{2}$; ${Fe}^{2 +}$=[Ar]$3d^{6}$
Number of unpaired electrons, $n$=4
$\mu$=$\sqrt{n(n + 2) =}\sqrt{4(4 + 2)} = 4.89$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.