Q. Excess of KI reacts with $CuSO_{4}$ solution and then $Na_{2}S_{2}O_{3}$ solution is added to it. Which of the statement is incorrect for this reaction?
A) $CuI_{2}$ is formed
B) $Na_{2}S_{2}O_{3}$ is oxidised
C) $Cu_{2}I_{2}$ is formed
D) Evolved $I_{2}$ is reduced
Explanation
The correct answer is Option A: $CuI_{2}$ is formed.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.