Q. Prussian blue is due to formation of
A) $Fe\left\lbrack Fe(CN)_{6} \right\rbrack_{3}$
B) $Fe_{2}\lbrack Fe(CN)_{6}\rbrack$
C) $Fe_{4}\left\lbrack Fe(CN)_{6} \right\rbrack_{3}$
D) $Fe_{3}\lbrack Fe(CN)_{6}\rbrack$
Explanation
(c)
$3Fe(CN)_{2} + 4Fe(CN)_{3} \rightarrow Fe_{4}\left\lbrack Fe(CN)_{6} \right\rbrack_{3}$ or $Fe_{7}C_{18}N_{18}$
Prussian blue
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.