(c)
$Ti^{3 +} \rightarrow 3d^{1},\ 4s^{0}$
$Sc^{3 +} \rightarrow 3d^{0}$
$Mn^{2 +} \rightarrow 3d^{5},\ 4s^{0}$
$Zn^{2 +} \rightarrow 3d^{10},\ 4s^{0}$
In $Mn^{2 +}$ number of unpaired electrons =5. So, it has maximum magnetic moment according to the formula
$\mu = \sqrt{n(n + 2)}\ BM$